#elif I2CDEV_IMPLEMENTATION = I2CDEV_BUILTIN_FASTWIRE Comment this line if having compilation difficulties join I2C bus (I2Cdev library doesn't do this automatically) Volatile bool mpuInterrupt = false // indicates whether MPU interrupt pin has gone high MPU6050 mpu(0圆9) // Average_Accel_X(Filter_Window) ĪverageValue Average_Accel_Y(Filter_Window) ĪverageValue Average_Accel_Z(Filter_Window) AD0 low = 0圆8 (default for SparkFun breakout and InvenSense evaluation board) specific I2C addresses may be passed as a parameter here #if I2CDEV_IMPLEMENTATION = I2CDEV_ARDUINO_WIRE Arduino Wire library is required if I2Cdev I2CDEV_ARDUINO_WIRE implementation #include "MPU6050.h" // not necessary if using MotionApps include file RotatedGravity= gravity*rotationMatrix + gravity*rotationMatrix + gravity*rotationMatrix You had some array indexing errors in the original rotation matrix multiplication, which I overlooked at first. You are certainly on the right track! Edit: our posts crossed.
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“Real programmers set the universal constants at the start such that the universe evolves to contain the disk with the data they want.” - xkcd Where to Go From Here?Ĭoders get paid six figures and more because they can solve problems more effectively using machine intelligence and automation. The source is simply that the list.pop() method removes the element with value 0. This code snippet is from a StackOverflow question. The Inde圎rror also frequently occurs if you iterate over a list but you remove elemen t s as you iterate over the list: l = Inde圎rror When Modifying a List as You Iterate Over It Eliminate the source of the faulty index.Figure out the faulty index just before the error is thrown.But the general debugging strategy remains even for advanced code projects: Note that this is a minimal example and it doesn’t make a lot of sense. The correct code is, therefore: # CORRECT CODE The final one is the index i=4 which points to the fifth element in the list (remember zero-based indexing: Python starts indexing at index 0!).īut the list has only four elements, so you need to reduce the number of indices you’re iterating over. You can now see all indices used to retrieve an element. The result of this code snippet is still an error.įile "C:\Users\xcent\Desktop\code.py", line 6, in So, let’s insert a print statement before that line: lst = The error message tells you that the error appears in line 5. # File "C:\Users\xcent\Desktop\code.py", line 5, in Here’s an example of wrong code that will cause the error to appear: # WRONG CODE This way, you’ll have your wrong index in the shell right before the error message. To achieve this, you can print the index that causes the error before you use it on the list. To pin down the exact problem, check the value of the index just before the error occurs. So, how can you fix the code? Python tells you in which line and on which list the error occurs. It’s a common mistake: The index of the third element is 2 because the index of the first list element is 0. The call lst would retrieve the third list element 'Carl'.ĭid you try to access the third element with index 3? The following graphic shows that the maximal index in your list is 2. The element with index 3 doesn’t exist in the list with three elements. Let’s have a look at an example where this error arises: lst =
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